k^2/3-2k^1/3=8

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Solution for k^2/3-2k^1/3=8 equation: 


k in (-oo:+oo)

(k^2)/3-((2*k^1)/3) = 8 // - 8

(k^2)/3-((2*k^1)/3)-8 = 0

(k^2)/3+(-2/3)*k-8 = 0

1/3*k^2-2/3*k-8 = 0

DELTA = (-2/3)^2-(-8*1/3*4)

DELTA = 100/9

DELTA > 0

k = ((100/9)^(1/2)+2/3)/(1/3*2) or k = (2/3-(100/9)^(1/2))/(1/3*2)

k = 6 or k = -4

k in { -4, 6 }

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